This week I want to share one of the biggest challenges slash disappointments about UofT [also csc165] in general. I have been keeping up with the course material since the very first week, didn't miss any class, review the material frequently and I spent two full weeks [every day more than 4 hours] to work on my first assignment. By the time I have to do my midterm, I was just too tired and confused [because the longer i think about csc165 material, questions, assignment etc, the more I reach at the point the only thing i know is i don't know anything] and although the midterm was fairly easy, very similar to assignment and previous midterms I got super confused and did very well.. so this is a big challenge for me at UofT in general.. it's really disappointing to get a bad mark after you put so much afford in something.. I guess, I have to teach myself somehow not to be disappointed and keep working more and more..
Anyway.. this week I'd like to blog about question 3 [from the midterm] and question 4 [from the assignment.] This is a funny story!
Although I made it correct on the assignment(!), I got very confused during the midterm [ I guess, time pressure and stress] and answered that S3 is equal to S4 and this question is not solvable! LOL! After I left the midterm I suddenly realize how to solve it.
So now I'll walk you over how I found the solution:
Assume all x belongs to D
Then if x is P, then Q must be true #S3 is true
Then P and Q intersection must be empty #S4 is false
Then P(x) and Q (x) intersection must be {}
Because if there does not exist any element in P and Q interaction , S4 is false, however, S3 becomes vacuously true!
Anyway.. this week I'd like to blog about question 3 [from the midterm] and question 4 [from the assignment.] This is a funny story!
Although I made it correct on the assignment(!), I got very confused during the midterm [ I guess, time pressure and stress] and answered that S3 is equal to S4 and this question is not solvable! LOL! After I left the midterm I suddenly realize how to solve it.
So now I'll walk you over how I found the solution:
Assume all x belongs to D
Then if x is P, then Q must be true #S3 is true
Then P and Q intersection must be empty #S4 is false
Then P(x) and Q (x) intersection must be {}
Because if there does not exist any element in P and Q interaction , S4 is false, however, S3 becomes vacuously true!